2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    A hollow sphere of radius \[0.1\text{ }m\] has a charge of \[5\times {{10}^{-8}}C.\]. The potential at a distance of \[5\text{ }cm\]from the centre of the  sphere is \[=\left( \frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}\,\,N{{m}^{2}}\,\,{{C}^{-2}} \right)\]

    A)  \[4000\,V\]

    B)  \[4500\,V\]

    C)  \[5000\,V\]

    D)  \[6000\,V\]

    Correct Answer: B

    Solution :

    Potential \[V=\frac{Q}{4\pi {{\varepsilon }_{0}}r}\] Given, \[Q=5\times {{10}^{-8}}C,\frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}},R=0.1m\] \[V=\frac{5\times {{10}^{-8}}\times 9\times {{10}^{9}}}{0.1}\] \[=\frac{450}{0.1}=4500V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner