J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    The temperature coefficient of the resistance of a wire is\[0.00125\text{ }per{{\text{ }}^{o}}C\]. At \[300\text{ K}\]its resistance is \[1\Omega \]. The resistance of wire will be \[2\,\,\Omega ,\] at

    A)  \[1154\,\,K\]            

    B)  \[1100\,\,K\]

    C)  \[1400\text{ }K\]            

    D)  \[1127\,\,K\]

    Correct Answer: D

    Solution :

    Note None of the four options are correct. through option  is close to correct answer. \[{{R}_{t}}={{R}_{0}}(1+\alpha t)\] \[1={{R}_{0}}(1+0.00125\times 27)\] ?.(i) \[2={{R}_{0}}(1+0.00125\times t)\] ?.(ii) From Eqs. (i) and (ii) \[t={{848}^{o}}C=1121K\]


You need to login to perform this action.
You will be redirected in 3 sec spinner