A) \[{{[NiC{{l}_{4}}]}^{2-}}\]
B) \[{{[NI{{(CN)}_{4}}]}^{2-}}\]
C) \[{{[Cr{{(N{{H}_{3}})}_{6}}]}^{3+}}\]
D) \[{{[CuC{{l}_{4}}]}^{2-}}\]
Correct Answer: B
Solution :
ln\[\text{Ni(CN}{{\text{)}}_{\text{4}}}\text{,Ni}\]is in \[\text{ds}{{\text{p}}^{2}}\] hybridised and the shape is square planar. The square planar geometry results in diamagnetic magnetism as all the electrons are paired resulting in zero spin.
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