A) 1-propanol
B) 2-propanol
C) ethanol
D) butanol
Correct Answer: A
Solution :
\[\underset{\text{propanal}}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,\,+\,LiAl{{H}_{4}}/{{H}_{2}}O\xrightarrow{{}}\] \[\underset{1-\text{propanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,\]
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