A) \[C{{H}_{3}}COCl\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[C{{H}_{3}}COOH\]
D) \[C{{H}_{3}}C{{H}_{2}}COOH\]
Correct Answer: D
Solution :
\[C{{H}_{3}}{{H}_{2}}l\xrightarrow[-Kl]{KCN}C{{H}_{3}}C{{H}_{2}}CN\xrightarrow{{{H}_{3}}{{O}^{+}}/{{H}_{2}}O}\] \[C{{H}_{3}}C{{H}_{2}}CHO\xrightarrow{{{H}_{3}}{{O}^{+}}/{{H}_{2}}O}\underset{\text{propanoic}\,\text{acid}}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
