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J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    The value of \[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{{{\log }_{e}}x}\] is

    A)  \[1\]

    B)  \[0\]

    C)  Not defined         

    D)  \[-1\]

    Correct Answer: A

    Solution :

    \[\underset{x\to 1}{\mathop{\lim }}\,\frac{x-1}{{{\log }_{e}}x};\,\,\left( from\frac{0}{0} \right)\] [Use L? Hospital rule] \[=\underset{x\to 1}{\mathop{\lim }}\,\frac{1}{1/x}=\underset{x\to 1}{\mathop{\lim }}\,x=1\]


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