A) \[a\pm \sqrt{1-\frac{{{b}^{2}}}{{{a}^{2}}}}y\]
B) \[b\pm \sqrt{1-\frac{{{a}^{2}}}{{{b}^{2}}}}y\]
C) \[a\pm \sqrt{1-\frac{{{b}^{2}}}{{{a}^{2}}}}\,x\]
D) \[b\pm \sqrt{1-\frac{{{a}^{2}}}{{{b}^{2}}}}\,x\]
Correct Answer: C
Solution :
We know that, the focal distance or radii of the point \[(x,y)\] from the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{{{b}^{2}}2}}=1,\,\,(a>b)}{{}}\] \[=a\pm ex\] \[\Rightarrow \] \[a\pm \sqrt{\frac{{{a}^{2}}-{{b}^{2}}}{{{a}^{2}}}}.x=a\pm \sqrt{1-\frac{{{b}^{2}}}{{{a}^{2}}}}.x\]
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