A) \[\{(x,y):\,x,\,y\,\in R,{{x}^{2}}=y\}\]
B) \[\{(x,y):\,x,\,y\,\in R,{{y}^{2}}=x\}\]
C) \[\{(x,y):\,x,\,y\,\in R,x={{y}^{3}}\}\]
D) \[\{(x,y):\,x,\,y\,\in R,y={{x}^{3}}\}\]
Correct Answer: B
Solution :
\[\because \] \[{{y}^{2}}=x\,\,\,\,\,\Rightarrow \,\,\,\,\,y=\pm \sqrt{x}\] is one value of x gives two values of y. So, \[\{(x,y):\,x,\in R,\,{{y}^{2}}=x\}\] is not a function.
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