2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    A straight wire of mass 300 g and length \[2.5\text{ }m\]carries a current of \[3.5\text{ }A\]. It is suspended in mid-air by a uniform horizontal magnetic field B. What is the magnitude of the magnetic field?

    A)  \[0.654\text{ }T\]

    B)  \[0.336\text{ }T\]

    C)  \[1.576\text{ }T\]

    D)  \[0.939\text{ }T\]

    Correct Answer: B

    Solution :

    Here weight of the wire is balanced by the extene magnetic force. So,          \[Bil=mg\] \[B=\frac{mg}{il}\] \[=\frac{300\times {{10}^{-3}}\times 10}{35\times 2.5}=0.34\,T\]


You need to login to perform this action.
You will be redirected in 3 sec spinner