A) \[1.8\,\,nC\]
B) \[2\,\,nC\]
C) \[1\,\,nC\]
D) \[1.5\,\,nC\]
Correct Answer: B
Solution :
For a conducting charged sphere, the electric field outside the sphere \[(E)=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{Q}{{{r}^{2}}}\] \[1.8\times {{10}^{3}}=9\times {{10}^{9}}\times \frac{Q}{{{(0.1)}^{2}}}\] \[Q=\frac{1.8\times {{10}^{3}}\times {{10}^{-2}}}{9\times {{10}^{9}}}\] \[=2\times {{10}^{-9}}C\] \[=2\,\,nC\]
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