J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    A compound microscope has a magnification of\[30\]. The focal length of the eye-piece is \[5\text{ }cm\] If the final image is formed at the least distance of distinct vision \[(25\,\,cm)\] the magnification produced by the objective is

    A)  \[10\]     

    B)  \[7.5\]

    C)  \[5\]  

    D)  \[15\]

    Correct Answer: C

    Solution :

    \[m=30\] \[{{f}_{e}}=5\,cm\] \[m={{m}_{o}}\times {{m}_{e}}\] \[m={{m}_{o}}\times \left( 1+\frac{D}{{{f}_{e}}} \right)\] \[30={{m}_{0}}\left( 1+\frac{25}{5} \right)\Rightarrow {{m}_{o}}=5\]


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