A) \[55/82\]
B) \[40/82\]
C) \[45/82\]
D) \[36/82\]
Correct Answer: C
Solution :
We have, \[{{T}_{n}}=\frac{n(n-4)}{{{n}^{2}}+1}\] \[\therefore \] 9th term, \[{{T}_{9}}=\frac{9(9-4)}{{{9}^{2}}+1}=\frac{9\times 5}{81+1}=\frac{45}{82}\]
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