J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    The carbon resistor has the color band sequence of green, orange, blue and silver. The value of resistance will be

    A) \[64\times {{10}^{7}}\pm 20%\,\,\Omega \]

    B) \[53\times {{10}^{6}}\pm 20%\,\,\Omega \]

    C) \[64\times {{10}^{7}}\pm 10%\,\,\Omega \]

    D) \[53\times {{10}^{6}}\pm 10%\,\,\Omega \]

    Correct Answer: D

    Solution :

    Figure and multiplier corresponding to the given colours are
    Colour Figure Multiplier
    Green 5 105
    Orange 3 103
    Blue 6 106
    Tolerance corresponding to silver is 10%. Thus, the value of resistance is \[R=53\times {{10}^{6}}\pm 10%\,\,\Omega \]


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