J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    The dimension of magnetic flux is

    A)  \[[ML{{T}^{-1}}{{A}^{-1}}]\]

    B)  \[[M{{L}^{-1}}T{{A}^{-2}}]\]

    C)  \[[M{{L}^{-2}}{{T}^{2}}{{A}^{-2}}]\]   

    D)  \[[M{{L}^{2}}{{T}^{-2}}{{A}^{-1}}]\]

    Correct Answer: D

    Solution :

    Magnetic flux  \[(\phi )=\] (Magnetic field) \[\times \] (Area) or         \[[\phi ]=[B][A]\] \[=\frac{[Force][Area]}{[Current][Length]}=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[A][L]}\] \[|\phi |=[M{{L}^{2}}{{T}^{-2}}{{A}^{-1}}]\]


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