A) \[M,{{X}_{2}}\]
B) \[{{H}_{2}},{{X}_{2}}\]
C) \[{{H}_{2}},{{O}_{2}}\]
D) \[M,{{O}_{2}}\]
Correct Answer: B
Solution :
Given, \[{{E}^{o}}_{{{M}^{+}}/M}=-1.2\,V\] \[{{E}^{o}}_{{{x}_{2}}/{{x}^{-}}}=-1.1\,V\] \[{{E}^{o}}_{{{O}_{2}}/{{H}_{2}}O}=1.23\,V\] On electrolysis of aqueous solution of salt MX. The products obtained depends on the given \[{{\text{E}}^{\text{o}}}\]values i.e. cathodic reaction will be one with higher \[{{\text{E}}^{\text{o}}}_{\text{red}}\]value. Anodic reaction will be one with higher \[{{\text{E}}^{\text{o}}}_{oxi}\]value or lower \[{{\text{E}}^{\text{o}}}_{red}\]value. Hence, the products are \[{{H}_{2}}\]and \[{{X}_{2}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
