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J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    \[\frac{{{K}_{p}}}{{{K}_{C}}}\]for the reaction \[A(g)+2{{B}_{2}}(g)\xrightarrow{{}}A{{B}_{2}}(g)\]is

    A) \[RT\]

    B) \[{{(RT)}^{2}}\]

    C)  \[\frac{1}{RT}\]

    D) \[\frac{1}{{{(RT)}^{2}}}\]

    Correct Answer: D

    Solution :

     \[A(g)+2B(g)\xrightarrow{{}}A{{B}_{2}}(g)\] \[{{K}_{p}}={{K}_{C}}{{(RT)}^{\Delta n}}_{g}\] \[\Delta {{n}_{g}}=\]change in number of moles = moles of product - moles of reactant \[=1-3=-2\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}{{(RT)}^{-2}}\] \[\Rightarrow \] \[\frac{{{K}_{p}}}{{{K}_{C}}}=\frac{1}{{{(RT)}^{2}}}\]


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