A) \[140\text{ }N{{C}^{-1}}\]
B) \[153\text{ }N{{C}^{-1}}\]
C) \[163\text{ }N{{C}^{-1}}\]
D) \[133\text{ }N{{C}^{-1}}\]
Correct Answer: B
Solution :
\[\frac{{{E}_{0}}}{{{B}_{0}}}=c\]or\[{{E}_{0}}=c{{B}_{0}}\] \[=3\times {{10}^{8}}\times 510\times {{10}^{-9}}N{{C}^{-1}}\] \[=153N{{C}^{-1}}\]
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