JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        The mean and the variance of a binomial distribution are 4 and 2 respectively. Then, the probability of 2 successes is

    A)  \[\frac{128}{256}\]                        

    B)  \[\frac{219}{256}\]

    C)  \[\frac{37}{256}\]                                           

    D)  \[\frac{28}{256}\]

    Correct Answer: D

    Solution :

                    Given,\[np=4\]and\[npq=2\] \[\therefore \]  \[q=\frac{1}{2}\Rightarrow p=\frac{1}{2}\]and\[n=8\] \[\therefore \]Required probability\[{{=}^{8}}{{C}_{2}}{{\left( \frac{1}{2} \right)}^{2}}{{\left( \frac{1}{2} \right)}^{6}}\]                                 \[=28{{\left( \frac{1}{2} \right)}^{8}}=\frac{28}{256}\]


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