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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2011

  • question_answer
        If a particle is acted on by constant forces \[4i+j-3k\]and\[3i+j-k\]it displace from a point\[(i+2j+3k)\]to the point\[5i+4j+k,\] what is the total work done by the forces?

    A)  50 units              

    B)  40 units

    C)  24 units              

    D)  0 unit

    Correct Answer: B

    Solution :

                    F = resultant force \[=4i+j-3k+3i+j-k=7i+2j-4k\] \[\therefore \] d = displacement \[=5i+4j+k-i-2j-3k\] \[=4i+2j-2k\] \[\therefore \]\[W=\] work done\[=F.d\] \[=(7i+2j-4k).(4i+2j-2k)\] \[=28+4+8=40\]units


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