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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
        The breaking force for a wire of diameter\[D\]of a material is F. The breaking force for a wire of the same material of radius D is

    A)  F                                            

    B)  2F

    C)  \[\frac{F}{4}\]                                  

    D)  4F

    Correct Answer: C

    Solution :

                    Breaking stress\[=\frac{breaking\text{ }force}{area}=\]constant \[\frac{F}{\left( \frac{\pi {{D}^{2}}}{4} \right)}=\frac{F}{\pi {{D}^{2}}}\] \[\frac{F}{\pi {{D}^{2}}}=4\frac{F}{\pi {{D}^{2}}}\] \[F=4F\] \[F=\frac{F}{4}\]


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