question_answer

    A tank is filled with water upto height H. When a hole is made at a distance h below the level of water. What will be the horizontal range of water jet?

A)  \[2\sqrt{h(H-h)}\]          

B)  \[4\sqrt{h(H+h)}\]

C)  \[4\sqrt{h(H-h)}\]          

D)  \[2\sqrt{h(H+h)}\]

Correct Answer: A

Solution :

                Applying Bernoullis theorem, The velocity of water at point \[v=\sqrt{2gh}\] Time taken to reach point C is t So,     \[H-h=\frac{1}{2}g{{t}^{2}}\]                 \[t=\sqrt{\frac{2(H-h)}{g}}\]                       ?.(i) Now, horizontal range \[R=vt\]                 \[=\sqrt{2gh}\times \sqrt{\frac{2(H-h)}{g}}=2\sqrt{(H-h)}h\]