A) 2s
B) 4s
C) 1s
D) 6s
Correct Answer: B
Solution :
When a cone filled with water is revolved in a vertical circle, then the velocity at the highest point is given by \[v\ge \sqrt{gr}\] Also, \[v=r\omega =r\frac{2\pi }{T}\] Hence, \[\frac{2r\pi }{T}\ge \sqrt{rg}\] \[T\le \frac{2\pi r}{\sqrt{rg}}=2\pi \sqrt{\frac{r}{g}}=2\pi \sqrt{\frac{4}{9.8}}\] \[=2\times 3.14\times 0.6389=4.0s\] So, \[{{T}_{\max }}=4\,s\]
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