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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2012

  • question_answer
    To dissolve 0.9 g metal, 100 mL of\[1\text{ }N\text{ }HCl\]is used. What is the equivalent weight of metal?

    A)  7                                            

    B)  9

    C)  10                                         

    D)  6

    Correct Answer: B

    Solution :

                    \[1\text{ }N\text{ }HCl\]solution means; 36.5 g of\[HCl\]are dissolved in 1000 mL. (\[\because \] Equivalent wt. of\[HCl=36.5\]) \[\therefore \]100 mL of\[HCl\]solution contains\[HCl\] Similarly 100 mL of\[HCl\]solution contains Now, \[\frac{Eq.\text{ }wt.\text{ }of\text{ }metal}{Weight\text{ }of\text{ }metal\text{ }in\text{ }solution}\] \[=\frac{Eq.\text{ }wt.\text{ }of\text{ }acid}{Weight\text{ }of\text{ }acid\text{ }in\text{ }solution}\]                 \[\frac{E}{0.9}=\frac{36.5}{3.65}\]                 \[E=9\]


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