A) \[\sqrt{3}BM\]
B) \[\sqrt{8}BM\]
C) \[\sqrt{15}BM\]
D) \[\sqrt{24}BM\]
Correct Answer: C
Solution :
In\[Hg[Co{{(SCN)}_{4}}],\]cobalt is in\[+2\]state with three unpaired electrons in 3d orbital. Thus, \[\mu =\sqrt{3(3+2)}=\sqrt{15}BM\]
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