A) \[3.72\times {{10}^{-20}}c{{m}^{3}}\]
B) \[2.69\times {{10}^{19}}c{{m}^{3}}\]
C) \[22400c{{m}^{3}}\]
D) \[22400\times 6.02\times {{10}^{23}}c{{m}^{3}}\]
Correct Answer: A
Solution :
One mole of gas\[={{N}_{0}}\]molecules = 22400 mL at STP Average volume per molecule \[=\frac{22400}{{{N}_{0}}}=3.72\times {{10}^{-20}}c{{m}^{3}}\]
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