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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    Bond energy of\[N-H,H-H\]and\[N\equiv N\] bonds are\[{{q}_{1}},{{q}_{2}}\]and\[{{q}_{3}};\Delta H\]of\[{{N}_{2}}+3{{H}_{2}}\xrightarrow[{}]{{}}2N{{H}_{3}}\]is

    A)  \[{{q}_{3}}+3{{q}_{2}}-2{{q}_{1}}\]         

    B)  \[2{{q}_{1}}-{{q}_{3}}-2{{q}_{2}}\]

    C)  \[{{q}_{3}}+3{{q}_{2}}-6{{q}_{1}}\]         

    D)  \[{{q}_{1}}+{{q}_{2}}-{{q}_{3}}\]

    Correct Answer: C

    Solution :

                    \[\Delta H=(BE)\]of all bonds in reactants - (BE) of all bonds in products \[={{q}_{3}}+3{{q}_{2}}-6{{q}_{1}}\] (each\[N{{H}_{3}}\]has three\[N-H\] bonds)


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