JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    A fluid of volume \[1\,\,L\] is subjected to a pressure change of\[{{10}^{7}}N/{{m}^{2}}\]. As a result its volume changes by \[0.4\,\,c{{m}^{3}}\]. The bulk modulus of the fluid is:

    A) \[2.5\times {{10}^{10}}N/{{m}^{2}}\]     

    B)  \[2.5\times {{10}^{11}}N/{{m}^{2}}\]

    C)  \[2.5\times {{10}^{9}}N/{{m}^{2}}\]      

    D)  \[2.5\times {{10}^{15}}N/{{m}^{2}}\]

    Correct Answer: A

    Solution :

    The bulk modulus \[(B)\] of a fluid is given by                 \[B=\frac{\Delta P}{\Delta V/V}=\frac{\Delta PV}{\Delta V}\] Given,\[V=1\,\,L=1000\,\,cc=1000\times {{10}^{-6}}{{m}^{3}}\]                                                                 \[={{10}^{-3}}{{m}^{3}}\] \[\Delta P={{10}^{7}}N/{{m}^{2}},\,\,\Delta V=0.4\,\,c{{m}^{3}}=0.4\times {{10}^{-6}}{{m}^{3}}\] \[\therefore \]  \[B=\frac{1\times {{10}^{7}}\times {{10}^{-3}}}{0.4\times {{10}^{-6}}}=\frac{1}{0.4}\times {{10}^{10}}\] \[\Rightarrow \]               \[B=2.5\times {{10}^{10}}N/{{m}^{2}}\]


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