JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    If the degrees of freedom of the molecules of a gas are n, the ratio of its two specific heats\[({{C}_{P}}/{{C}_{V}})\]will be:

    A) \[1+\frac{2}{n}\]                             

    B)  \[1-\frac{2}{n}\]

    C)  \[1+\frac{1}{n}\]                            

    D)  \[2-\frac{1}{n}\]

    Correct Answer: A

    Solution :

    Key Idea: Mayor's formula is\[{{C}_{P}}-{{C}_{V}}=R\]. Internal energy of a gram mole of a perfect gas having n degrees of freedom is                 \[U=N\left( n\cdot \frac{1}{2}kt \right)=\frac{n}{2}RT\]                 \[{{C}_{V}}=\frac{dU}{dt}=\frac{d}{dt}\left( \frac{n}{2}RT \right)=\frac{n}{2}R\] From Mayor?s formula                 \[{{C}_{P}}-{{C}_{V}}=R\] \[\Rightarrow \]               \[{{C}_{P}}=R+{{C}_{V}}\] \[\Rightarrow \]               \[{{C}_{P}}=R+\frac{n}{2}R=\left( \frac{n}{2}+1 \right)R\] \[\therefore \]  \[\gamma =\frac{{{C}_{P}}}{{{C}_{V}}}=\frac{\left( \frac{n}{2}+1 \right)R}{\frac{n}{2}R}=1+\frac{2}{n}\]


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