A) \[C{{H}_{3}}-CH=NNHCONHC{{H}_{3}}\]
B) \[C{{H}_{3}}-CH=N-NHCON{{H}_{2}}\]
C) \[C{{H}_{3}}CH=N-NHCON{{H}_{2}}\]
D) \[C{{H}_{3}}-CH=N-NHCONH-CON{{H}_{2}}\]
Correct Answer: C
Solution :
Key idea: Write reaction to find correct answer \[\underset{acetaldehyde}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-H}}\,+\underset{semicarbazide}{\mathop{{{H}_{2}}NNHCON{{H}_{2}}}}\,\xrightarrow{{}}\] \[\underset{acetaldehyde\,\,semicarbazone}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} H \\ || \end{smallmatrix}}{\mathop{C}}\,=NNHCON{{H}_{2}}}}\,\]
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