JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    If\[\sqrt{a+ib}=x+iy\], then possible value of\[\sqrt{a-ib}\]is:

    A) \[{{x}^{2}}+{{y}^{2}}\]                  

    B) \[\sqrt{{{x}^{2}}-{{y}^{2}}}\]

    C) \[x+iy\]               

    D) \[x-iy\]

    Correct Answer: D

    Solution :

    Given that                 \[\sqrt{a+ib}=x+iy\] \[\Rightarrow \]               \[a+ib={{x}^{2}}-{{y}^{2}}+2i\,\,xy\] \[\Rightarrow \]               \[a={{x}^{2}}-{{y}^{2}},\,\,b=2xy\]                           ? (i) Now, we assume                 \[\sqrt{a-ib}=x-iy\] \[\Rightarrow \]               \[a-ib={{x}^{2}}-{{y}^{2}}-2i\,xy\] \[\Rightarrow \]               \[a={{x}^{2}}-{{y}^{2}},\,\,b=2xy\]                           ? (ii) \[\therefore \]  Eqs. (i) and (ii) are equal. \[\therefore \]  Option  is correct.


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