A) \[y=c{{e}^{\int{P\,\,dx}}}\]
B) \[x=c{{e}^{-\int{P\,\,dx}}}\]
C) \[y=c{{e}^{-\int{P\,\,dx}}}\]
D) None of these
Correct Answer: C
Solution :
Given differential equation is \[\frac{dy}{dx}+P(x)y=0\] \[\Rightarrow \] \[\frac{dy}{y}=-P(x)dx\] On integrating both sides, we get \[\log y=-\int{P}\,\,dx-\log c\] \[\Rightarrow \] \[y=c{{e}^{-\int{P\,\,dx}}}\]
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