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JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    The speed of wave in a medium is \[650\,\,m/s\]. If \[3500\] waves are passing through a point in the medium in \[1.67\,\,\min \], then its wavelength will be:

    A) \[16.25\,\,m\]                  

    B) \[14.29\,\,m\]

    C)  \[18.57\,\,m\]                 

    D)  \[20.50\,\,m\]

    Correct Answer: C

    Solution :

    As we have given that \[3500\] waves are passing through a point in the medium in \[1.67\,\,\min \], so frequency of the wave,                 \[n=\frac{3500}{1.67\times 60}\approx 35/s\] Hence, wavelength of the wave,                 \[\lambda =\frac{v}{n}\]                 \[=\frac{650}{35}=18.57\,\,m\]


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