JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    The body is projected at such angle that the horizontal range is three times the greatest height. The angle of projection is:

    A) \[{{43}^{o}}8'\]                

    B) \[{{25}^{o}}8'\]

    C)  \[{{33}^{o}}7'\]               

    D) \[{{53}^{o}}1'\]

    Correct Answer: D

    Solution :

    Horizontal range of a body is given by                 \[R=\frac{{{u}^{2}}\sin 2\theta }{g}\] where \[\theta \] is the angle at which body is projected. The greatest height of body is given by                 \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] Given,   \[R=3H\]                 \[\frac{{{u}^{2}}\sin 2\theta }{g}=3\times \frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] or            \[2\sin \theta \cos \theta =\frac{3}{2}{{\sin }^{2}}\theta \] or            \[\tan \theta =\frac{4}{3}\] \[\therefore \]  \[\theta ={{\tan }^{-1}}\left( \frac{4}{3} \right)={{53}^{o}}1'\]


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