A) \[\frac{3}{10}m/s\]
B) \[20\,\,m/s\]
C) \[\frac{20}{3}m/s\]
D) \[15\,\,m/s\]
Correct Answer: C
Solution :
Key Idea: In an inelastic collision, linear momentum is conserved. Since, in given collision the two bodies stick to each other, so collision is inelastic. Applying conservation of linear momentum. \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=({{m}_{1}}+{{m}_{2}})v\] ... (i) where, \[v\] is the velocity of joint body. Given,\[{{m}_{1}}=10\,\,kg,\,\,{{v}_{1}}=10\,\,m/s,\,\,{{m}_{2}}=5\,\,kg,\] \[{{v}_{2}}=0\]. Substituting the values in Eq. (i), we get \[10\times 10+5\times 0=(10+5)v\] or \[100=5v\] or \[v=\frac{100}{15}=\frac{20}{3}m/s\]
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