A) \[0.13m/{{s}^{2}}\]
B) \[0.16m/{{s}^{2}}\]
C) \[0.18m/{{s}^{2}}\]
D) \[0.34m/{{s}^{2}}\]
Correct Answer: A
Solution :
The distance travelled by the body in nth second is given by \[{{s}_{n}}=u+\frac{1}{2}a(2n-1)\] ... (i) Since, body starts from rest, so\[u=0\]. Given, \[{{s}_{n}}=110\,\,cm,\,\,n=9\] Substituting the values in Eq. (i), we get \[110=0+\frac{1}{2}a(2\times 9-1)\] or \[110=\frac{a}{2}\times 17\] \[\therefore \] \[a=\frac{2\times 110}{17}\approx 13\,\,cm/{{s}^{2}}\] or \[a=0.13\,\,m/{{s}^{2}}\]
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