JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    If the direction ratios of a line are \[1,\,\,-3,\,\,2,\] then the direction cosines of the line are :

    A) \[\frac{1}{\sqrt{14}},\,\,\frac{-3}{\sqrt{14}},\,\,\frac{2}{\sqrt{14}}\]        

    B) \[\frac{1}{\sqrt{14}},\,\,\frac{2}{\sqrt{14}},\,\,\frac{3}{\sqrt{14}}\]

    C) \[\frac{-1}{\sqrt{14}},\,\,\frac{3}{\sqrt{14}},\,\frac{-2}{\sqrt{14}}\]          

    D)  \[\frac{-1}{\sqrt{14}},\,\,\frac{-2}{\sqrt{14}},\,\,\frac{-3}{\sqrt{14}}\]

    Correct Answer: A

    Solution :

    Key Idea: If \[a,\,\,\,b\] and \[c\] are the direction ratios of a line, then the direction cosines of a line are                 \[l=\frac{a}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}},\,\,m=\frac{b}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}}\] \[n=\frac{c}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}}\] Given direction ratios are \[1,\,\,-3\] and \[2\]. \[\therefore \]Direction cosines are \[l=\frac{1}{\sqrt{{{1}^{2}}+{{(-3)}^{2}}+{{2}^{2}}}},\,\,m=-\frac{3}{\sqrt{{{1}^{2}}+{{(-3)}^{2}}+{{2}^{2}}}}\] \[n=\frac{2}{\sqrt{{{1}^{2}}+{{(-3)}^{2}}+{{(2)}^{2}}}}\] \[i.e.,\] \[l=\frac{1}{\sqrt{14}},\,\,m=-\frac{3}{\sqrt{14}},\,\,n=\frac{2}{\sqrt{14}}\] Note: In any line has only one direction cosine but the direction ratios may be more than one.


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