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JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    If \[A\] and \[B\] are two independent events, then \[P(A+B)\] is equal to:

    A) \[P(A)+P(B)-P(A)P(B)\]

    B) \[P(A)-P(B)\]

    C) \[P(A)+P(B)\]

    D)  \[P(A)+P(B)+P(A)P(B)\]

    Correct Answer: A

    Solution :

    Key Idea: If \[A\] and \[B\] are independent, then                 \[P(A\cap B)=P(A)P(B)\] \[\therefore \]  \[P(A\cup B)=P(A+B)\]                 \[=P(A)+P(B)-P(A\cap B)\]                 \[=P(A)+P(B)-P(A)P(B)\] Note: If \[A\] and \[B\] are two mutually exclusive events, then\[P(A\cap B)=0\].


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