JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    As shown, in figure, a planet revolves in elliptical orbit around the sun. Where is \[KE\] of the planet maximum?

    A)  At\[{{P}_{4}}\]                

    B)  At\[{{P}_{1}}\]

    C)  At\[{{P}_{2}}\]                

    D)   At\[{{P}_{3}}\]

    Correct Answer: A

    Solution :

    Key Idea: Angular momentum is conserved. From law of conservation of angular momentum, we have                 \[J=I\omega =\]constant where, \[I\] is moment of inertia and \[\omega \] is angular velocity. Also,      \[I=M{{R}^{2}}\]and\[\omega =\frac{v}{R}\] \[\therefore \]  \[v\propto \frac{1}{R}\] At \[{{P}_{4}}\] the value of \[R\] is minimum, hence the velocity is maximum or kinetic energy will be maximum.


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