A) \[67.5\,\,g\]
B) \[9.45\,\,g\]
C) \[6.75\,\,g\]
D) \[94.5\,\,g\]
Correct Answer: A
Solution :
Key Idea: Molarity \[=\frac{mole\,\,of\,\,solute}{volume\,\,of\,\,solution\,\,in\,\,L}\] \[=\frac{mass/molecular\,\,mass}{V\,\,in\,\,L}\] Given molarity\[=2.5\,\,M\] Volume \[=300\,\,mL=\frac{300}{1000}L\] Molecular mass of oxalic acid\[{{(COOH)}_{2}}\] \[={{(12+16\times 2+1)}_{2}}=90\] \[\therefore \] \[2.5=\frac{mass/90}{300/1000}\] or \[2.5=\frac{mass}{90}\times \frac{1000}{300}\] \[\therefore \] \[mass=\frac{90\times 300\times 2.5}{1000}\] \[=67.5\,\,g\]
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