A) \[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\]
B) \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\]
C) \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}{{H}_{2}}O\]
D) \[2NO+{{O}_{2}}2N{{O}_{2}}\]
Correct Answer: A
Solution :
Key Idea: According to Le-Chatelier's principle, the reactions in which number of moles are increasing are favourable at low pressure. [a]\[PC{{l}_{5}}PC{{l}_{3}}+C{{l}_{2}}\] Moles of reactants\[=1\] Moles of products\[=2\] \[\because \]Number of moles are increasing. \[\therefore \]The reaction is favoured at low pressure. [b]\[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] \[\because \]Number of moles are decreasing. \[\therefore \]The reaction is favoured at high pressure. [c]\[{{H}_{2}}+\frac{1}{2}{{O}_{2}}{{H}_{2}}O\] \[\because \]Number of moles are decreasing. \[\therefore \]The reaction is favoured at high pressure. [d]\[2NO+{{O}_{2}}2NO\] \[\because \]Number of moles are decreasing. \[\therefore \]The reaction is favoured at high pressure.
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