A) \[s{{p}^{2}}\]
B) \[s{{p}^{3}}{{d}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[sp\]
Correct Answer: A
Solution :
Key Idea: Hybridisation \[=\frac{1}{2}\] [number, of valence\[{{e}^{-}}\] in central atom \[+\] number of monovalent atoms charge on cation \[+\] charge on onion] For\[S{{O}_{2}}\] Hybridisation\[=\frac{1}{2}(6+0-0+0)\] \[=3\] \[\therefore \] \[s{{p}^{2}}-\]hybridisation
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