JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    If\[\cos \theta +\cos 2\theta +\cos 3\theta =0\], the general value of\[\theta \]is:

    A) \[\theta =2m\pi \pm \pi /4\]

    B) \[\theta =m\pi +{{(-1)}^{n}}2\pi /3\]

    C) \[\theta =m\pi +{{(-1)}^{n}}\pi /3\]

    D) \[\theta =2m\pi \pm 2\pi /3\]

    Correct Answer: D

    Solution :

    Given that,\[\cos \theta +\cos 2\theta +\cos 3\theta =0\] \[\Rightarrow \]               \[(\cos \theta +\cos 3\theta )+\cos 2\theta =0\] \[\Rightarrow \]               \[2\cos 2\theta \cos \theta +\cos 2\theta =0\] \[\Rightarrow \]               \[\cos 2\theta (2\cos \theta +1)=0\] \[\Rightarrow \]               \[\cos 2\theta =0\]and\[2\cos \theta +1=0\] \[\Rightarrow \]               \[2\theta =\cos \frac{\pi }{2}\] and \[\cos \theta =-\frac{1}{2}\] \[\Rightarrow \]               \[\theta =m\pi \pm \frac{\pi }{4}\]and\[\theta =2m\pi \pm \frac{2\pi }{3}\]


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