JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    Three point charges \[1C,\,\,\,2C\] and \[3C\] are placed at the comers of an equilateral triangle of side \[1\,\,m\]. The work done in bringing these charges to the vertices of a smaller similar triangle of side\[0.5\,\,m\]is:

    A) \[2.7\times {{10}^{10}}J\]                            

    B) \[9.9\times {{10}^{10}}J\]

    C) \[10.8\times {{10}^{10}}J\]                         

    D) \[5.4\times {{10}^{10}}J\]

    Correct Answer: B

    Solution :

    Key Idea: Work done is equal to potential energy Potential energy \[(U)\] is given by                 \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{r}\] For three sets of charges                 \[U={{U}_{1}}+{{U}_{2}}+{{U}_{3}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\] \[({{q}_{1}}{{q}_{2}}+{{q}_{2}}{{q}_{3}}+{{q}_{3}}{{q}_{1}}).\frac{1}{r}\] \[\Rightarrow \]               \[U=\frac{1}{4\pi {{\varepsilon }_{0}}}(1\times 2+2\times 3+3\times 1)\left( \frac{1}{0.5}-\frac{1}{1} \right)\]                     \[=9\times {{10}^{9}}\times 11\]                     \[=9.9\times {{10}^{10}}J\]


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