JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    In the Wheatstone's bridge shown below, in order to balance the bridge we must have:

    A) \[{{R}_{1}}=3\Omega ,\,\,{{R}_{2}}=3\Omega \]

    B) \[{{R}_{1}}=6\Omega ,\,\,{{R}_{2}}=1.5\Omega \]

    C)  \[{{R}_{1}}=1.5\Omega ,\,{{R}_{2}}=\]any finite value

    D) \[{{R}_{1}}=3\Omega ,\,\,{{R}_{2}}=\]any finite value

    Correct Answer: D

    Solution :

    Key idea: Given circuit is a balanced Wheatstone's bridge. The ratio of resistances in the opposite arms of the circuit is equal\[i.e.,\]\[\frac{10}{30}=\frac{{{R}_{1}}}{9}\]\[\Rightarrow \]\[{{R}_{1}}=3\Omega \]and resistance \[{{R}_{2}}\] may have any finite value.


You need to login to perform this action.
You will be redirected in 3 sec spinner