A) \[2\,\,molar\]
B) \[2\,\,molal\]
C) \[1\,\,normal\]
D) \[1\,\,molal\]
Correct Answer: B
Solution :
Key Idea: Molality\[=\frac{moles\,\,of\,\,solute}{mass\,\,of\,\,solvent\,\,in\,\,kg}\] \[=\frac{mass\,\,of\,\,solute/molecular\,\,weight}{mass\,\,of\,\,solvent\,\,in\,\,kg}\] Given mass of solute\[=117\,\,g\], molecular mass of\[NaCl=58.5\] mass of solvent\[=1000\,\,g=1\,\,kg\] molality\[=\frac{117/58.5}{1}=2\] \[=2\]
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