A) \[42\,\,J\,\,mo{{l}^{-1}}{{K}^{-1}}\]
B) \[21\,\,J\,\,mo{{l}^{-1}}{{K}^{-1}}\]
C) \[84\,\,J\,\,mo{{l}^{-1}}{{K}^{-1}}\]
D) \[8.4\,\,J\,\,mo{{l}^{-1}}{{K}^{-1}}\]
Correct Answer: D
Solution :
Key Idea:\[\Delta S=\frac{\Delta H}{T}\] where\[\Delta S=\]entropy of vaporisation. \[\Delta H=\]enthalpy of vaporisation\[=840\,\,J/mol\] \[T=-{{173}^{o}}C=-173+273=100\,\,K\] \[\therefore \] \[\Delta S=\frac{840}{100}=8.4\,\,J\,\,mo{{l}^{-1}}{{K}^{-1}}\]
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