A) ethanol
B) ethanol
C) methanol
D) propanone
Correct Answer: C
Solution :
Key Idea: Iodoform test is given by compounds having \[C{{H}_{3}}CO\]or\[C{{H}_{2}}OH\] group. \[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(a) \\ has\,\,C{{H}_{2}}OH\,\,group \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}}\,-OH}}\,\] \[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(b) \\ has\,\,C{{H}_{3}}CO\,\,group \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-H}}\,\] \[\underset{\begin{smallmatrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(d) \\ has\,\,C{{H}_{3}}CO\,\,group \end{smallmatrix}}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\] \[\therefore \]All of them give iodoform test. \[C{{H}_{3}}OH\](choice\[c)\] does not have \[C{{H}_{3}}CO\] or \[C{{H}_{2}}OH\] group and so it does not give iodoform test.
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