A) \[HCHO\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}OC{{H}_{3}}\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: B
Solution :
Key Idea: \[HCHO+Grignard\,\,reagent\xrightarrow{hydrolysis}\] \[{{1}^{o}}alcohol\] \[Any\,\,other\,\,aldehdye+Grignard\text{ }reagent\] \[\xrightarrow{Hydrolysis}{{2}^{o}}alcohol\] \[Ketone+Grignard\,\,reagent\]\[\xrightarrow{Hydrolysis}\] \[{{3}^{o}}alcohol\] \[\underset{(a)}{\mathop{HCHO}}\,\underset{\begin{smallmatrix} \,\,\,\,\,\,\,(b) \\ aldehyde \end{smallmatrix}}{\mathop{C{{H}_{3}}CHO}}\,\underset{\begin{smallmatrix} \,\,\,(c) \\ ether \end{smallmatrix}}{\mathop{C{{H}_{3}}OC{{H}_{3}}}}\,\underset{\begin{smallmatrix} \,\,\,(d) \\ ketone \end{smallmatrix}}{\mathop{C{{H}_{3}}COC{{H}_{3}}}}\,\] \[\therefore \,\,C{{H}_{3}}CHO\]is correct choice. \[C{{H}_{3}}CHO+C{{H}_{3}}MgBr\xrightarrow{{}}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} OMgBr \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\] \[\underset{{{2}^{o}}alcohol}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} \downarrow {{H}_{2}}O \\ OH \\ | \end{smallmatrix}}{\mathop{C}}}\,-H}}\,\]
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