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JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    The first overtone frequency of a wave on string of length \[2\,\,m\] is \[250\,\,Hz\]. Then, its velocity is:

    A) \[1000\,\,m/s\]                

    B) \[25\,\,m/s\]

    C)  \[100\,\,cm\]                   

    D) \[10\,\,cm\]

    Correct Answer: C

    Solution :

    The first overtone of a wave on string is given by                                 \[n=\frac{v}{\lambda }\] where \[1\] is wavelength, \[v\] the velocity and \[n\] the frequency. Given, \[\lambda =l\] (in first overtone) \[\therefore \]  \[n=\frac{v}{l}\] \[\Rightarrow \]               \[v=nl=250\times 2=500\,\,m/s\]


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