JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    If path difference becomes \[(2n-1)\frac{\lambda }{2}\] then:

    A)  white fringe is formed

    B)  bright fringe is formed

    C)   uniform illumination is obtained

    D)   dark fringe is formed

    Correct Answer: D

    Solution :

    Key Idea: Path difference is odd multiple of\[\frac{\lambda }{2}\]. Given path difference\[=(2n-1)\frac{\lambda }{2}\]. which is an odd multiple of\[\frac{\lambda }{2}\]. Hence, destructive interference takes place and dark fringe is formed.


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